A strange puzzle??

[turk]

YOUR AGE BY EATING OUT
>(you may need to use a calculator)
> Don't tell me your age; you probably would tell a falsehood
> anyway-but
> your waiter may know!
>
> YOUR AGE BY DINER & RESTAURANT MATH
>
> Work this out as you read ... It takes less than a minute .
>
> Be sure you don't read the bottom until you've worked it out!
>
> This is not one of those waste of time things, it's fun.
>
> 1. First of all, pick the number of times a week that you would
> like to go out to eat (more than once but less than 10)
>
> 2. Multiply this number by 2 (just to be bold)
>
> 3. Add 5
>
> 4. Multiply it by 50
>
> 5. If you have already had your birthday this year add 1756 ....
> If you haven't, add 1755.
>
> 6. Now subtract the four digit year that you were born.
>
>









You should have a three digit number................
>
> The first digit of is your original number
> (I.e., how many times you want to go out to restaurants in a week.)
>
> The next two numbers are YOUR AGE! (Oh YES, it is!!!!!)
>
> 2006 IS THE ONLY YEAR THIS WILL EVER WORK......SO SPREAD IT AROUND
> WHILE IT LASTS
>
tell me any opinions as to how this works thanks

[GANAMOHA]

 +1000

[bounda]

314

[kiwibonga]

You multiply that random number by 2 then by 50, as if you just moved it two places to the left...

Since you also add 5 * 50, you have ?00 + 250

1756 + 250 = 2006

The result you need to subtract the year of your birth from is 2006 + ?00.

In other words... ?00 + 2006 - year ...... which is actually ?00 + your age

[GANAMOHA]

The result you need to subtract the year of your birth from is 2006 + ?00.

In other words... ?00 + 2006 - year ...... which is actually ?00 + your age

I get it so in other words instead of doing something fancy he just adds the extra digit to throw you off the simplicity of this equation. thanks