ummm...................................................what??
http://www.blizzard.com/press/040401.shtml
a = b
a2 = a * b
a2 + a2 = a2 + a * b
2a2 = a2 + a * b
2a2 - 2(a * b) = a2 + a * b - 2(a * b)
2a2 - 2(a * b) = a2 - a * b
Which can be written...
2(a2 - a * b) = 1(a2 - a * b)
Cancel the (a2 - a * b) from both sides...
1 = 2.
~Squeek
Ps - I know the "trick" about it... don't ruin it for others [|)]
lol
10x - x = 9.99999999 - 0.999999999
9x = 8.9999999991
x = .9999999999
(if i may add: duh)
did you read that from the Blizzard April Fools thing Nag? Or somewhere else?
quote:
10x - x = 9.99999999 - 0.999999999
9x = 8.9999999991
How did you get 8.999999999
1 ???
Did you notice the "..." which should mean infinite repetition (as in limit tends to)...?
quote:
(if i may add: duh)
Not yet! [|)]
And for Squeek's one, I think you cannot that easily cancel (a2-ab); it has a special value... [|)]
lim 10x-x
x-> 1
Nagual, its not hard to add or subtract EPSILON by using ROUNDOFF ERROR. I see no trick.
Ok squeek even though it is very obvious I will not ruin it for others. Others, if you dont see whats wrong with his proof that 2=1, look closer, because its obviously not true.
quote:
Originally posted by Squeek
a = b
a2 = a * b
a2 + a2 = a2 + a * b
2a2 = a2 + a * b
2a2 - 2(a * b) = a2 + a * b - 2(a * b)
2a2 - 2(a * b) = a2 - a * b
Which can be written...
2(a2 - a * b) = 1(a2 - a * b)
Cancel the (a2 - a * b) from both sides...
1 = 2.
~Squeek
Ps - I know the "trick" about it... don't ruin it for others [|)]
HAHAHAHAHAHA...how did you come up with this equation?
Correct me if I make a really stupid comment but. Look at the fat lines. How did you cancel the -2( a * b ) out on the right side but leave it on the other side.
It's like 4-2 = 6-4
4-2 = 6
4 = 8
???
quote:
Originally posted by Nagual
Can you find the trick...? [|)]
x = 0.999999999...
10x = 9.99999999...
10x - x = 9.99999999... - 0.999999999...
9x = 9
x = 1
=> 1 = 0.999999999...
Isn't this just the roundof error??? because my calculator gives for 9x=9 when x=9,99999999999 (11 9ns after the comma or more)
quote:
How did you cancel the -2( a * b ) out on the right side but leave it on the other side.
Adkha, look at the sign:
2a2 - 2(a * b) = a2
+ a * b - 2(a * b)
2a2 - 2(a * b) = a2
- a * b
yes I think it does
to lighten the meaning of moron into a person capable of function,
I would say the moron would be inclined to make the mistakes that others might point at and say "Hey look at the moron, he is so immoral. What a maroon>"
therefore the moron serves a fine example. and in fact does start the course of morality. Am I trippin or did I just say that gotta go to bed.
x is equal to x or close enough except in nuclear anatomy.
it seems to be a dumn question or trick question pardon the pun
I always thought all those porported math formulas were b.s.
After all a letter does not explain what is happening. It is just a reasoning symbology Archimedies made up.
It is mere symbolism representing a higher and truer science of math
a = b = =+ _ bla bla bla
To explain true mathmatical expression do you not need the written or spoken word. The math we learn is given to us as if we were already masters of the field the equations simply exist because Archimedies had no paper and he was in a hurry.
If you all would like there are funny stories about him to research such as the discovery of buoyency and his death.
you didn't figure it out, did you?
If 1=one,
then one as a person is = to oneself,
then where does one come from,
if in the beginning in relationship to its end,
they are one in the same, and cancel each other out,
then should not 1=0?
thelou, 1 (beginning) - 1 (end) = 0
yay found the answer [:D]
A nice trick.
This one is pretty much easy...
quote:
Originally posted by Squeek
a = b
...
Which can be written...
2(a2 - a * b) = 1(a2 - a * b)
(a
2 - a * b) = 0 ,because a=b
so..
2(0) = 1(0) or just 0 = 0
Thanks for the challenge !
I'm still trying to solve the first one.. Are you sure there is a trick !? [xx(]
I dont know the actual trick but a simpler way of thinking about this would be like this...
1/3 = 0.333333333...
2/3 = 0.666666666...
0.333333... + 0.6666666... = 0.99999999...
which also is...
3/3 aka 1.
Who ever previously said Squeek randomly must have found my missing rubber ducky. [|)]
1/3 = 0.333333333...
2/3 = 0.666666666...
0.333333... + 0.6666666... - epsilon = 0.99999999...
0.333333... + 0.6666666... = 0.99999999... + epsilon = 1
Addressing the original problem, Nagual, 0.999... is equal to 1 mathematically. Think of it this way, the difference between 1 and 0.999... is 0.000...1, so the 1 is in the infinite placeholder in the decimal. In other words 0.000...1 can be written 1/infinity, or more precisely as lim (1/x) as x->infinity. These each equal zero. Therefore, the difference between 1 and 0.999... is 0, and by definition, for two numbers to be different, their difference must be greater than 0. So we can conclude that 1 and 0.999... are the same number, or 0.999...=1. So, you just stated this in another way; it is not a mathematical anomaly.
Are you actually allowed to put an x on one side and what x equals on the other side? from line three, you have that . . . which, in other words, could just be written . . .
10x-x=9.99999999... - x or
10x-0.99999999... =9.99999999... - 0.99999999...
Answers?
10x-0.99999999...=9, which =
10(0.999999999...) - 0.99999999...=9, which =
9.99999999... - 0.99999999 = 9, which =
9=9, which =
1
If we actually had minds, you'd be screwing with them [|)]
Can you find the trick...? [|)]
x = 0.999999999...
10x = 9.99999999...
10x - x = 9.99999999... - 0.999999999...
9x = 9
x = 1
=> 1 = 0.999999999...